Optimal. Leaf size=172 \[ \frac {26 a^3 e^2 \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{21 d \sqrt {e \cos (c+d x)}}-\frac {26 a^3 (e \cos (c+d x))^{5/2}}{35 d e}+\frac {26 a^3 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{21 d}-\frac {26 \left (a^3 \sin (c+d x)+a^3\right ) (e \cos (c+d x))^{5/2}}{63 d e}-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{5/2}}{9 d e} \]
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Rubi [A] time = 0.19, antiderivative size = 172, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2678, 2669, 2635, 2642, 2641} \[ \frac {26 a^3 e^2 \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{21 d \sqrt {e \cos (c+d x)}}-\frac {26 a^3 (e \cos (c+d x))^{5/2}}{35 d e}+\frac {26 a^3 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{21 d}-\frac {26 \left (a^3 \sin (c+d x)+a^3\right ) (e \cos (c+d x))^{5/2}}{63 d e}-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{5/2}}{9 d e} \]
Antiderivative was successfully verified.
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Rule 2635
Rule 2641
Rule 2642
Rule 2669
Rule 2678
Rubi steps
\begin {align*} \int (e \cos (c+d x))^{3/2} (a+a \sin (c+d x))^3 \, dx &=-\frac {2 a (e \cos (c+d x))^{5/2} (a+a \sin (c+d x))^2}{9 d e}+\frac {1}{9} (13 a) \int (e \cos (c+d x))^{3/2} (a+a \sin (c+d x))^2 \, dx\\ &=-\frac {2 a (e \cos (c+d x))^{5/2} (a+a \sin (c+d x))^2}{9 d e}-\frac {26 (e \cos (c+d x))^{5/2} \left (a^3+a^3 \sin (c+d x)\right )}{63 d e}+\frac {1}{7} \left (13 a^2\right ) \int (e \cos (c+d x))^{3/2} (a+a \sin (c+d x)) \, dx\\ &=-\frac {26 a^3 (e \cos (c+d x))^{5/2}}{35 d e}-\frac {2 a (e \cos (c+d x))^{5/2} (a+a \sin (c+d x))^2}{9 d e}-\frac {26 (e \cos (c+d x))^{5/2} \left (a^3+a^3 \sin (c+d x)\right )}{63 d e}+\frac {1}{7} \left (13 a^3\right ) \int (e \cos (c+d x))^{3/2} \, dx\\ &=-\frac {26 a^3 (e \cos (c+d x))^{5/2}}{35 d e}+\frac {26 a^3 e \sqrt {e \cos (c+d x)} \sin (c+d x)}{21 d}-\frac {2 a (e \cos (c+d x))^{5/2} (a+a \sin (c+d x))^2}{9 d e}-\frac {26 (e \cos (c+d x))^{5/2} \left (a^3+a^3 \sin (c+d x)\right )}{63 d e}+\frac {1}{21} \left (13 a^3 e^2\right ) \int \frac {1}{\sqrt {e \cos (c+d x)}} \, dx\\ &=-\frac {26 a^3 (e \cos (c+d x))^{5/2}}{35 d e}+\frac {26 a^3 e \sqrt {e \cos (c+d x)} \sin (c+d x)}{21 d}-\frac {2 a (e \cos (c+d x))^{5/2} (a+a \sin (c+d x))^2}{9 d e}-\frac {26 (e \cos (c+d x))^{5/2} \left (a^3+a^3 \sin (c+d x)\right )}{63 d e}+\frac {\left (13 a^3 e^2 \sqrt {\cos (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx}{21 \sqrt {e \cos (c+d x)}}\\ &=-\frac {26 a^3 (e \cos (c+d x))^{5/2}}{35 d e}+\frac {26 a^3 e^2 \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{21 d \sqrt {e \cos (c+d x)}}+\frac {26 a^3 e \sqrt {e \cos (c+d x)} \sin (c+d x)}{21 d}-\frac {2 a (e \cos (c+d x))^{5/2} (a+a \sin (c+d x))^2}{9 d e}-\frac {26 (e \cos (c+d x))^{5/2} \left (a^3+a^3 \sin (c+d x)\right )}{63 d e}\\ \end {align*}
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Mathematica [C] time = 0.07, size = 66, normalized size = 0.38 \[ -\frac {32 \sqrt [4]{2} a^3 (e \cos (c+d x))^{5/2} \, _2F_1\left (-\frac {13}{4},\frac {5}{4};\frac {9}{4};\frac {1}{2} (1-\sin (c+d x))\right )}{5 d e (\sin (c+d x)+1)^{5/4}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.75, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-{\left (3 \, a^{3} e \cos \left (d x + c\right )^{3} - 4 \, a^{3} e \cos \left (d x + c\right ) + {\left (a^{3} e \cos \left (d x + c\right )^{3} - 4 \, a^{3} e \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )\right )} \sqrt {e \cos \left (d x + c\right )}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (e \cos \left (d x + c\right )\right )^{\frac {3}{2}} {\left (a \sin \left (d x + c\right ) + a\right )}^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.26, size = 251, normalized size = 1.46 \[ -\frac {2 a^{3} e^{2} \left (1120 \left (\sin ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-2160 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-2800 \left (\sin ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+3240 \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+784 \left (\sin ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-840 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+1624 \left (\sin ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+195 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \EllipticF \left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}-120 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )-1162 \left (\sin ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+217 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{315 \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {-2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +e}\, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (e \cos \left (d x + c\right )\right )^{\frac {3}{2}} {\left (a \sin \left (d x + c\right ) + a\right )}^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (e\,\cos \left (c+d\,x\right )\right )}^{3/2}\,{\left (a+a\,\sin \left (c+d\,x\right )\right )}^3 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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